9(x+1)²(x-1)²-6(x²-1)y+y²

9(x+1)²(x-1)²-6(x²-1)y+y²
9(x+1)²(x-1)²-6(x²-1)y+y²

9(x+1)²(x-1)²-6(x²-1)y+y²
是要分解因式吧
=9【（x+1）（x-1）】² -6(x²-1)y + y²
=9（x²-1）² - 6(x²-1)y + y²
={3(x²-1)-y}²（完全平方公式）

9(x+1)²(x-1)²-6(x²-1)y+y²

=[3(x²-1)] ²-6(x²-1)y+y²

=[3(x²-1) ²- y] ²

=【[(√3) (x²-1)] ²- (√y) ²】²...

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9(x+1)²(x-1)²-6(x²-1)y+y²

=[3(x²-1)] ²-6(x²-1)y+y²

=[3(x²-1) ²- y] ²

=【[(√3) (x²-1)] ²- (√y) ²】²

=[(√3) (x²-1) + (√y)] [(√3) (x²-1) - (√y)]

=[(√3) (x+1)(x-1) + (√y)] [(√3) (x+1)(x-1) - (√y)]

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