作业帮为什么x趋近于无穷lim(3+x/6+x)^(x-1/2)=lim[(3/x+1)/(6/x+1)]^(x-1/2)=1不对
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/01 02:26:46
![为什么x趋近于无穷lim(3+x/6+x)^(x-1/2)=lim[(3/x+1)/(6/x+1)]^(x-1/2)=1不对](/uploads/image/z/10099129-49-9.jpg?t=%E4%B8%BA%E4%BB%80%E4%B9%88x%E8%B6%8B%E8%BF%91%E4%BA%8E%E6%97%A0%E7%A9%B7lim%283%2Bx%2F6%2Bx%29%5E%28x-1%2F2%29%3Dlim%5B%283%2Fx%2B1%29%2F%286%2Fx%2B1%29%5D%5E%28x-1%2F2%29%3D1%E4%B8%8D%E5%AF%B9)
为什么x趋近于无穷lim(3+x/6+x)^(x-1/2)=lim[(3/x+1)/(6/x+1)]^(x-1/2)=1不对
为什么x趋近于无穷lim(3+x/6+x)^(x-1/2)=lim[(3/x+1)/(6/x+1)]^(x-1/2)=1不对
为什么x趋近于无穷lim(3+x/6+x)^(x-1/2)=lim[(3/x+1)/(6/x+1)]^(x-1/2)=1不对
分式上下同时存在极限的时候,需要至少把其中一个化为定值,才可正确求极限