latex分段函数对齐问题求助代码是：\begin{equation}le{v_{a,b}}\left({i,j} \right)=\begin{cases}\max ({i,j}) &{\min({i,j})=0}\\\min \begin{cases} {le{v_{a,b}}\left( {i - 1,j} \right) + 1}\\ {le{v_{a,b}}\left( {i,j-1} \right) +

latex分段函数对齐问题求助代码是：\begin{equation}le{v_{a,b}}\left({i,j} \right)=\begin{cases}\max ({i,j}) &{\min({i,j})=0}\\\min \begin{cases} {le{v_{a,b}}\left( {i - 1,j} \right) + 1}\\ {le{v_{a,b}}\left( {i,j-1} \right) +
latex分段函数对齐问题求助

代码是：

\begin{equation}

le{v_{a,b}}\left({i,j} \right)=

\begin{cases}

\max ({i,j}) &{\min({i,j})=0}\\

\min

    \begin{cases}

    {le{v_{a,b}}\left( {i - 1,j} \right) + 1}\\

    {le{v_{a,b}}\left( {i,j-1} \right) + 1} &{else}\\

    {le{v_{a,b}}\left( {i - 1,j - 1} \right) + \left[ {{a_i} \ne {b_j}} \right]}\\

    \end{cases}

\end{cases}

\end{equation}

请问如何将右边的min和else对齐? 谢谢

latex分段函数对齐问题求助代码是：\begin{equation}le{v_{a,b}}\left({i,j} \right)=\begin{cases}\max ({i,j}) &{\min({i,j})=0}\\\min \begin{cases} {le{v_{a,b}}\left( {i - 1,j} \right) + 1}\\ {le{v_{a,b}}\left( {i,j-1} \right) +
代码太混乱且不合理,懒得改写了,你要对齐很简单,加了一句比较粗暴的语句即可实现,虽然很ugly,倒也可以应付你的文档了
\begin{equation}
le{v_{a,b}}\left({i,j} \right)=
\begin{cases}
\max ({i,j}) &{\hspace{-1.1cm}\min({i,j})=0}\\
\min
\begin{cases}
{le{v_{a,b}}\left( {i - 1,j} \right) + 1}\\
{le{v_{a,b}}\left( {i,j-1} \right) + 1} &{else}\\
{le{v_{a,b}}\left( {i - 1,j - 1} \right) + \left[ {{a_i} \ne {b_j}} \right]}\\
\end{cases}
\end{cases}
\end{equation}