解方程:3/(x-1)-(x+2)/(x∧2-x)=0是[3/(x-1)]-[(x+2)/(x∧2-x)]=0

解方程:3/(x-1)-(x+2)/(x∧2-x)=0是[3/(x-1)]-[(x+2)/(x∧2-x)]=0
解方程:3/(x-1)-(x+2)/(x∧2-x)=0
是[3/(x-1)]-[(x+2)/(x∧2-x)]=0

解方程:3/(x-1)-(x+2)/(x∧2-x)=0是[3/(x-1)]-[(x+2)/(x∧2-x)]=0
3/(x-1)-(x+2)/x(x-1)=0
两边乘x(x-1)
3x-(x+2)=0
3x-x-2=0
x=1
经检验,x=1时分母x-1=0
是增根,舍去
所以方程无解