问几道七年级数学题(有过程)能做几道做几道,但要正确(x-1)^3+(x-2)^3+(2x-3)^3(x+1)^4+(x^2-1)^2+(x-1)^4(x+y)^4+x^4+y^4x^4+2x^3+4x^2+2x+3x^3-3px^2+(3p^2-q^2)x-p(p^2-q^2)(xy+1)(x+1)(y+1)+xy(x^3+y^3)^2-4xy[x^4+x^2y^2+y^4-2xy(x^2-xy

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问几道七年级数学题(有过程)能做几道做几道,但要正确(x-1)^3+(x-2)^3+(2x-3)^3(x+1)^4+(x^2-1)^2+(x-1)^4(x+y)^4+x^4+y^4x^4+2x^3+4x^2+2x+3x^3-3px^2+(3p^2-q^2)x-p(p^2-q^2)(xy+1)(x+1)(y+1)+xy(x^3+y^3)^2-4xy[x^4+x^2y^2+y^4-2xy(x^2-xy

问几道七年级数学题(有过程)能做几道做几道,但要正确(x-1)^3+(x-2)^3+(2x-3)^3(x+1)^4+(x^2-1)^2+(x-1)^4(x+y)^4+x^4+y^4x^4+2x^3+4x^2+2x+3x^3-3px^2+(3p^2-q^2)x-p(p^2-q^2)(xy+1)(x+1)(y+1)+xy(x^3+y^3)^2-4xy[x^4+x^2y^2+y^4-2xy(x^2-xy
问几道七年级数学题(有过程)能做几道做几道,但要正确
(x-1)^3+(x-2)^3+(2x-3)^3
(x+1)^4+(x^2-1)^2+(x-1)^4
(x+y)^4+x^4+y^4
x^4+2x^3+4x^2+2x+3
x^3-3px^2+(3p^2-q^2)x-p(p^2-q^2)
(xy+1)(x+1)(y+1)+xy
(x^3+y^3)^2-4xy[x^4+x^2y^2+y^4-2xy(x^2-xy+y^2)]
x^3(a+1)-xy(x-y)(a-b)+y^3(b+1)
(ab+cd)(a^2-b^2+c^2-d^2)+(ac+bd)(a^2+b^2-c^2-d^2)
xyz(x^3+y^3+z^3)-x^3y^3-y^3z^3-z^3x^3
已知x+y-2是多项式x^2+axy+by^2-5x+y+6的一个因式,求a、b的值并分解因式
^2是2次方,^3是3次方

问几道七年级数学题(有过程)能做几道做几道,但要正确(x-1)^3+(x-2)^3+(2x-3)^3(x+1)^4+(x^2-1)^2+(x-1)^4(x+y)^4+x^4+y^4x^4+2x^3+4x^2+2x+3x^3-3px^2+(3p^2-q^2)x-p(p^2-q^2)(xy+1)(x+1)(y+1)+xy(x^3+y^3)^2-4xy[x^4+x^2y^2+y^4-2xy(x^2-xy
(x-1)^3+(x-2)^3+(2x-3)^3
=(x^3-3x^2+3x-1)+(x^3-6x^2+12x-8)+(8x^3-36x^2+54x-27)
=10x^3-45x^2+69x-36
(x+1)^4+(x^2-1)^2+(x-1)^4
=(x+1)^2*(x+1)^2+(x^2-1)^2+(x-1)^2*(x-1)^2
=(x^4+4x^3+6x^2+4x+1)+(x^4-2x^2+1)+(x^4-4x^3+6x^2-4x+1)
=3x^4+10x^2+3
受不了了
题倒是不难
就是打字实在是太麻烦了……
就写到这吧
难受死了

∧是幂的意思

次方吧

好象看不懂

" ^ "是啥意思?