作业帮y=(x/128000-3x/80+8)*100/x,求导y=(x/128000-3x/80+8)*100/x,用导数求出极限…要详细步骤……
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y=(x/128000-3x/80+8)*100/x,求导y=(x/128000-3x/80+8)*100/x,用导数求出极限…要详细步骤……
y=(x/128000-3x/80+8)*100/x,求导
y=(x/128000-3x/80+8)*100/x,用导数求出极限…要详细步骤……
y=(x/128000-3x/80+8)*100/x,求导y=(x/128000-3x/80+8)*100/x,用导数求出极限…要详细步骤……
y=(x^3/128000-3x/80+8)*100/x=(x^3/128000-3x/80+8)*100x^(-1) y'=[(x^3/128000-3x/80+8)*100x^(-1)]' =(x^3/128000-3x/80+8)'*100x^(-1)+(x^3/128000-3x/80+8)*[100x^(-1)]' =(3x^2/128000-3/80)*100x^(-1)+(x^3/128000-3x/80+8)*100*(-1)x^(-2) =(3x^2/128000-3/80)*100x^(-1)-(x^3/128000-3x/80+8)*100x^(-2) =[(3x^3/128000-3x/80)-(x^3/128000-3x/80+8)]*100x^(-2) =100(x^3/64000-8)*x^(-2) 如有不妥请回复.
【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2=
(x+y)/y=8/3则x/y=__ y/x-y=___
(x+y)/y=8/3则x/y=__ y/x-y=___
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推倒公式:(x+y)(x*x-3x+y*y)=x*x*x+y*y*y怎么做.
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{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是（）?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8？(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
化简y=|x-1|+|x-4|-|3x-8|
3^x+2x=y,x