4(x-4)=2(y-1)(x-4)+(y-1)=5 怎么解x和y

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4(x-4)=2(y-1)(x-4)+(y-1)=5 怎么解x和y

4(x-4)=2(y-1)(x-4)+(y-1)=5 怎么解x和y
4(x-4)=2(y-1)(x-4)+(y-1)=5 怎么解x和y

4(x-4)=2(y-1)(x-4)+(y-1)=5 怎么解x和y
设x-4=A,y-1=B,对两个方程进行等量代换得:4A=2B, A*A+B*B=5 , B=2A,A*A+B*B=5 A*A+2A*2A=5,5A*A=5,A*A=1,所以A=1或-1,解得A=1时B=2,A=-1时B=-2,因为x-4=A,y-1=B, 所以,x-4=1,y-1=2,或者x-4=-1,y-1=-2,解得x=5,y=3或者x=3,y=-1. 亲,请您采纳,您的采纳是我的动力,谢谢.

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