(1)已知a+b=2分之3,ab=1,化简(a-2)(b-2)的结果为多少、(2)a-b=1,ab=-2,则(a+1(b-1)=多少

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(1)已知a+b=2分之3,ab=1,化简(a-2)(b-2)的结果为多少、(2)a-b=1,ab=-2,则(a+1(b-1)=多少

(1)已知a+b=2分之3,ab=1,化简(a-2)(b-2)的结果为多少、(2)a-b=1,ab=-2,则(a+1(b-1)=多少
(1)已知a+b=2分之3,ab=1,化简(a-2)(b-2)的结果为多少、(2)a-b=1,ab=-2,则(a+1(b-1)=多少

(1)已知a+b=2分之3,ab=1,化简(a-2)(b-2)的结果为多少、(2)a-b=1,ab=-2,则(a+1(b-1)=多少
(1)
(a-2)(b-2)
=ab-2(a+b)+4
=1-2(3/2)+4
=2
(2)
(a+1)(b-1)
=ab-(a-b)-1
=-2-1-1
=-4

1)
(a-2)(b-2)
=ab-2(a+b)+4
=1-2(3/2)+4
=2
(2)
(a+1)(b-1)
=ab-(a-b)-1
=-2-1-1
=-4

(a-2)(b-2)=ab-2(a+b)+4=1-2×2分之3+4=2
(a+1)(b-1)=ab-(a-b)-1=-2-1-1=-4