作业帮[D68] The famous scientist,_____ a dinner party will be held tonight,it to arrive soon.A.in honour of him B.in his honourC.in whose honour D.in which honour翻译包括选项,并分析
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/29 10:53:32
![[D68] The famous scientist,_____ a dinner party will be held tonight,it to arrive soon.A.in honour of him B.in his honourC.in whose honour D.in which honour翻译包括选项,并分析](/uploads/image/z/10639245-21-5.jpg?t=%5BD68%5D+The+famous+scientist%2C_____+a+dinner+party+will+be+held+tonight%2Cit+to+arrive+soon.A.in+honour+of+him+B.in+his+honourC.in+whose+honour+D.in+which+honour%E7%BF%BB%E8%AF%91%E5%8C%85%E6%8B%AC%E9%80%89%E9%A1%B9%2C%E5%B9%B6%E5%88%86%E6%9E%90)
[D68] The famous scientist,_____ a dinner party will be held tonight,it to arrive soon.A.in honour of him B.in his honourC.in whose honour D.in which honour翻译包括选项,并分析
[D68] The famous scientist,_____ a dinner party will be held tonight,it to arrive soon.
A.in honour of him B.in his honour
C.in whose honour D.in which honour
翻译包括选项,并分析
[D68] The famous scientist,_____ a dinner party will be held tonight,it to arrive soon.A.in honour of him B.in his honourC.in whose honour D.in which honour翻译包括选项,并分析
翻译：这位著名的科学家,将很快到场（出席）那个为其庆祝而于今晚举行的宴会.
此题考查定语从句关系词用法.
1.主句是：The famous scientist is to arrive soon.
而括号中间是一个非限制性定语从句,修饰句子主语the famous scientist.
2.将其代入该定语从句中,变化为：
a dinner party will be held tonight (in the famous scientist's honour)
= (in the famous scientist's honour) a dinner party will be held tonight
= (in whose honour) a dinner party will be held tonight
其中,关系代词whose等同于先行词的所有格形式,在定语从句中充当定语.
3.另：此句也可以如此变化：
a dinner party will be held tonight (in honour of the famous scientist)
= (in honour of whom) a dinner party will be held tonight
其中,whom代替先行词the famous scientist,在定语从句中充当of的宾语.
4.上述两种变化各含有一个固定短语：
in one's honour = in honour of sb,意思是“为庆祝/为纪念/为表达对...的敬意”.
5.AB等于是一个单独的简单句,并不是定语从句,因为它们没有关系词引导；
D中的which只能代指事物sth,不能代指人sb,排除.