作业帮设实数xy满足x+y-3≤0,y-x/2≥0,x-1≥0,则求u=y/x-x/y的取值范围
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设实数xy满足x+y-3≤0,y-x/2≥0,x-1≥0,则求u=y/x-x/y的取值范围
设实数xy满足x+y-3≤0,y-x/2≥0,x-1≥0,则求u=y/x-x/y的取值范围
设实数xy满足x+y-3≤0,y-x/2≥0,x-1≥0,则求u=y/x-x/y的取值范围
设实数xy满足x+y-3≤0,y-x/2≥0,x-1≥0,则求u=y/x-x/y的取值范围
x+y-3≤0.(1)
y-(x/2)≥0,.(2)
x-1≥0.(3)
化出三条直线：x+y-3=0；y-(x/2)=0；x-1=0；三条直线的交点意次为A(1,2)；B(1,1/2)；
C(2,1)；动点(x,y)就在以这三点为顶点的△ABC内(含边界).
不难看出：1/2≤y/x≤2,2≥y/x≥1/2；
两式相减即得 -3/2≤y/x-x/y≤3/2.
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