3 (a的平方-2a-3) -5 (-5a的平方+a- 2)=

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3 (a的平方-2a-3) -5 (-5a的平方+a- 2)=

3 (a的平方-2a-3) -5 (-5a的平方+a- 2)=
3 (a的平方-2a-3) -5 (-5a的平方+a- 2)=

3 (a的平方-2a-3) -5 (-5a的平方+a- 2)=
3 (a的平方-2a-3) -5 (-5a的平方+a- 2)
=3a²-6a-9+25a²-5a+10
=28a²-11a+1
=(4a-1)(7a-1)

3 (a的平方-2a-3) -5 (-5a的平方+a- 2)
=3a^2-6a-9+25a^2-5a+10
=28a^2-11a+1
=(4a-1)(7a-1)

3a²-6a-9+25a²-5a+10
=28a²-11a+1