求对数方程根log3为底(x^2-10)=1+log3为底x

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求对数方程根log3为底(x^2-10)=1+log3为底x

求对数方程根log3为底(x^2-10)=1+log3为底x
求对数方程根log3为底(x^2-10)=1+log3为底x

求对数方程根log3为底(x^2-10)=1+log3为底x
log3(x²-10)=1+log3(x)
log3(x²-10)=log3(3)+log3(x)
log3(x²-10)=log3(3x)
x²-10=3x
x1=-2,x2=5