作业帮分式计算题,
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 02:33:03
分式计算题,
分式计算题,
分式计算题,
1/(x-1)+1/(1+x)
=(x+1)/[(x+1)(x-1)]+(x-1)/[(x+1)(x-1)]
=[(x+1)+(x-1)]/[(x+1)(x-1)]
=(2x)/(x²-1)
c/(ab)-a/(bc)
=c²/(abc)-a²/(abc)
=(c²-a²)/(abc)
=[(c+a)(c-a)]/(abc)
就是先分母通分，然后分子相加减就可以了
(3)1/(x-1)+1/(x+1)=(x+1)/[(x-1)(x+1)]+(x-1)/[(x-1)(x+1)]
=[(x+1)+(x-1)]/[(x-1)(x+1)]
=2x/(x²-1)
(4)c/ab-a/bc=c²/abc-a²/abc
=(c²-a²)/abc
(3)原式=（x+1)/(x-1)(x+1)+(x-1)/(x+1)(x-1)=2x/(x²-1)
(4)原式=c²/abc-a²/abc=(c+a)(c-a)/abc