诺x+3=7-y,a.b互为倒数,则1/2(x+y)+3ab的值是

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诺x+3=7-y,a.b互为倒数,则1/2(x+y)+3ab的值是

诺x+3=7-y,a.b互为倒数,则1/2(x+y)+3ab的值是
诺x+3=7-y,a.b互为倒数,则1/2(x+y)+3ab的值是

诺x+3=7-y,a.b互为倒数,则1/2(x+y)+3ab的值是
x+3=7-y
x+y=4
a.b互为倒数
ab=1
1/2(x+y)+3ab
=1/2*4+3*1
=5

x+3=7-y x+y=7-3=4
a.b互为倒数 ab=1

1/2(x+y)+3ab=1/2*4+3*1=2+3=5

由已知条件,x+y=4
a,b互为倒数,所以a*b=1
则1/2(x+y)+3ab=2+3=5