As in figure 2．In the circular ring of which center is point O．if AO⊥BO,and the area of the shAs in figure 2．In the circular ring of which center is point O．if AO⊥BO,and the area of the shadowy part is 25cm2 ,then the area of the circuiar

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As in figure 2．In the circular ring of which center is point O．if AO⊥BO,and the area of the shAs in figure 2．In the circular ring of which center is point O．if AO⊥BO,and the area of the shadowy part is 25cm2 ,then the area of the circuiar

As in figure 2．In the circular ring of which center is point O．if AO⊥BO,and the area of the shAs in figure 2．In the circular ring of which center is point O．if AO⊥BO,and the area of the shadowy part is 25cm2 ,then the area of the circuiar
As in figure 2．In the circular ring of which center is point O．if AO⊥BO,and the area of the sh
As in figure 2．In the circular ring of which center is point O．if AO⊥BO,and the area of the shadowy part is 25cm2 ,then the area of the circuiar ring equals to 
（π ≈3.14）
（A）147  （B）157 （C）167  （D）177
 





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As in figure 2．In the circular ring of which center is point O．if AO⊥BO,and the area of the shAs in figure 2．In the circular ring of which center is point O．if AO⊥BO,and the area of the shadowy part is 25cm2 ,then the area of the circuiar
Let OC=r, OA=R,
then R^2/2 - r^2/2 = 25
R^2 - r^2 = 50
Area of the ring = πR^2 - πr^2 = π (R^2 - r^2) = 50π = 157

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