作业帮一道简单的因式分解分解因式:(X+1)(x+2)(X+3)-6*7*8原式=(x+2-1)(X+2)((X+2+1)-(7-1)*7*(7+1)=(X+2)^2-(X+2)-7^3+7(这步是什么原理啊?怎么会相等?)=(X+2-7)[(X+2)^2+7(X+2)+7^2-1](这也解释一下,处学者)=(X-5)(X^2+11X+66)
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/29 05:58:11
=(X-5)(X^2+11X+66)](/uploads/image/z/5393856-48-6.jpg?t=%E4%B8%80%E9%81%93%E7%AE%80%E5%8D%95%E7%9A%84%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%3A%28X%2B1%29%28x%2B2%29%28X%2B3%29-6%2A7%2A8%E5%8E%9F%E5%BC%8F%3D%28x%2B2-1%29%28X%2B2%29%28%28X%2B2%2B1%29-%287-1%29%2A7%2A%287%2B1%29%3D%28X%2B2%29%5E2-%28X%2B2%29-7%5E3%2B7%28%E8%BF%99%E6%AD%A5%E6%98%AF%E4%BB%80%E4%B9%88%E5%8E%9F%E7%90%86%E5%95%8A%3F%E6%80%8E%E4%B9%88%E4%BC%9A%E7%9B%B8%E7%AD%89%3F%29%3D%28X%2B2-7%29%5B%28X%2B2%29%5E2%2B7%28X%2B2%29%2B7%5E2-1%5D%28%E8%BF%99%E4%B9%9F%E8%A7%A3%E9%87%8A%E4%B8%80%E4%B8%8B%2C%E5%A4%84%E5%AD%A6%E8%80%85%29%3D%28X-5%29%28X%5E2%2B11X%2B66%29)
一道简单的因式分解分解因式:(X+1)(x+2)(X+3)-6*7*8原式=(x+2-1)(X+2)((X+2+1)-(7-1)*7*(7+1)=(X+2)^2-(X+2)-7^3+7(这步是什么原理啊?怎么会相等?)=(X+2-7)[(X+2)^2+7(X+2)+7^2-1](这也解释一下,处学者)=(X-5)(X^2+11X+66)
一道简单的因式分解
分解因式:(X+1)(x+2)(X+3)-6*7*8
原式=(x+2-1)(X+2)((X+2+1)-(7-1)*7*(7+1)=(X+2)^2-(X+2)-7^3+7(这步是什么原理啊?怎么会相等?)
=(X+2-7)[(X+2)^2+7(X+2)+7^2-1](这也解释一下,处学者)
=(X-5)(X^2+11X+66)
一道简单的因式分解分解因式:(X+1)(x+2)(X+3)-6*7*8原式=(x+2-1)(X+2)((X+2+1)-(7-1)*7*(7+1)=(X+2)^2-(X+2)-7^3+7(这步是什么原理啊?怎么会相等?)=(X+2-7)[(X+2)^2+7(X+2)+7^2-1](这也解释一下,处学者)=(X-5)(X^2+11X+66)
=(x+2-1)(（X+2)(X+2+1)-(7-1)*7*(7+1)
=[(x+2-1)(X+2+1)(X+2)-(7-1)*(7+1)*7(这步中将x+2,7看成一个数,用平方差公式)
=[(X+2)^2-1]*(X+2)-(7^2-1)*7
=(X+2)^3-(X+2)-7^3+7
=(X+2-7)[(X+2)^2+7(X+2)+7^2]-(x-5)(相当于a^3-b^3)
=(x-5)[(x+2)²+7(x+2)+7²-1]
= (X-5)(X^2+11X+66)
(x+2-1)(x+2)(x+2+1)-(7-1)*7*(7+1)
=[(x+2)-1][(x+2)+1](x+2)-(7-1)(7+1)*7
=[(x+2)²-1](x+2)-（7²-1)*7
=(x+2)³-(x+2)-7³+7
(x+2)³-(x+2)-7³+7
=[(x+2)³-7³]-(x+2)+7
=[(x+2)-7][(x+2)²+7(x+2)+7²]-(x+2-7)
=(x+2-7)[(x+2)²+7(x+2)+7²-1]
原式=（X+2-1）(X+2)(X+2+1)-(7-1)7（7+1）
=[(X+2)^2-1](X+2)-(7^2-1)7
=(X+2)^3-(X+2)-7^3+7
=(X+2)^3-7^3+7-（X+2）
=(X+2-7)[(X+2)^2+7(X+2)+7^2]-(X+2-7)
=(X-5)(X^2+11X+67)-(X-5)
=(X-5)(X^2+11X+66)